-16x^2+4013x=-3250

Solution for -16x^2+4013x=-3250 equation:

-16x^2+4013x=-3250

We move all terms to the left:

-16x^2+4013x-(-3250)=0

We add all the numbers together, and all the variables

-16x^2+4013x+3250=0

a = -16; b = 4013; c = +3250;
Δ = b2-4ac
Δ = 40132-4·(-16)·3250
Δ = 16312169
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(4013)-\sqrt{16312169}}{2*-16}=\frac{-4013-\sqrt{16312169}}{-32}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(4013)+\sqrt{16312169}}{2*-16}=\frac{-4013+\sqrt{16312169}}{-32}
$